Hot Questions - Stack Exchange1d agoAbel Summation in Function Fields – mathoverflow.netOwen SharpeA variation of Abel's summation formula is ∑n=1Nf(n)g(n)=f(N)G(N)−∑n=1N−1(f(n+1)−f(n))G(n),\sum_{n = 1}^N f(n)g(n) = f(N)G(N) - \sum_{n = 1}^{N - 1} (f(n + 1) - f(n))G(n),∑n=1Nf(n)g(n)=f(N)G(N)−∑n=1N−1(f(n+1)−f(n))G(n), where G(n)=∑k=1ng(k).G(n) = \sum_{k = 1}^n g(k).G(n)=∑k=1ng(k). Suppose that $\alpha \in ...Read at Hot Questions - Stack ExchangeTagsmathematicsnumber-theory
