Qualitative Nature of the wave function under a certain potential

By putting the values of $V(x)$ at $a$ and point $b$ we get, \frac{\partial^2\psi}{\partial x^2}=\frac{2m}{\hbar^2}(-V_1-E)\psi \tag{1} and \frac{\partial^2\psi}{\partial x^2}=\frac{2m}{\hbar^2}(-V_2-E)\psi \tag{2} Now since $E >0$ we can say that the frequency of $\psi(x)$ is greater at point $b$ . since $|-V_1-E|<|-V_2-E|$ . And that is why as the particle goes from $a$ to $b$ its frequency goes up. But here, the correct answer is the 3rd one, where the frequency goes up but the amplitude is becoming less. I cant find any reason why that would happen and if my argument correct?